Gravity and mass of two objects

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To determine the ratio of two unknown masses, m1 and m2, with a particle positioned between them, the forces acting on the particle must be balanced, leading to the equation F1 = F2. The gravitational force equations F1 = G*m*m1/r1^2 and F2 = G*m*m2/r2^2 can be set equal to each other. Given that the particle is stationary at x = 0.515, the distances r1 and r2 can be expressed in relation to this position. The discussion emphasizes that m2 must be greater than m1 due to the stronger gravitational attraction. Ultimately, the ratio m2/m1 can be derived from the relationship between their respective distances from the particle.
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Homework Statement


There are two masses of unknown weight on a straight line with a small red particle between them. At x (Measured from the center of m1) = .515 the particle does not move. What is the ratio of the two masses? i.e. m2/m1.


Homework Equations





The Attempt at a Solution



So do I use F = G*m1*m2/r^2? Since the particle isn't moving then the forces are balanced does this mean F = 0 then?
 
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Hi AnkhUNC! :smile:
AnkhUNC said:
So do I use F = G*m1*m2/r^2?

Not exactly … you use F1 = G*m*m1/r1^2 and F2 = G*m*m2/r2^2 and F1 = F2.

Hint: what is the relationship between m1/m2 and r1/r2? :smile:
 
On the right side the min x = .043 on the left side the max is .957. It starts out at .5 though which is in the middle so I guess <- is 0 and -> is 1.

r1/r2 = 1, they're both .5 away so .5/.5 = 1.

m2 is greater than m1 because the attraction is stronger so does m2 = .515 and m1 = .485?
 
So F = G*m*m1*m2?
 
AnkhUNC said:
On the right side the min x = .043 on the left side the max is .957. It starts out at .5 though which is in the middle so I guess <- is 0 and -> is 1.

Sorry, AnkhUNC, but I honestly have no idea what this means. :confused: :cry:
tiny-tim said:
F1 = G*m*m1/r1^2 and F2 = G*m*m2/r2^2 and F1 = F2.

Hint: divide F1 by F2. :smile:
 
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