Green's Function for Helmholtz Eqn in Cube

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SUMMARY

The discussion focuses on finding the Green's Function for the Helmholtz Equation in a cube defined by the boundaries 0≤x,y,z≤L. The equation to solve is ∇²u + k²u = δ(x-x'), with boundary conditions u=0 on the cube's surface. The initial approach involves using separation of variables and matching conditions for one-dimensional cases, leading to the conclusion that a more efficient method is to apply the Fourier transform to derive the Green's function in three-dimensional space. This method simplifies the process by allowing the addition of a particular solution that satisfies the boundary conditions.

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Homework Statement


Find the Green's Function for the Helmholtz Eqn in the cube 0≤x,y,z≤L by solving the equation:
\nabla 2 u+k 2 u=δ(x-x')
with u=0 on the surface of the cube
This is problem 9-4 in Mathews and Walker Mathematical Methods of Physics

Homework Equations


Sines, they have the properties we're looking for.

The Attempt at a Solution


So, if the solution is in one dimension we obviously have
G=asinkx x<x' and
G=bsink(x-L) for x>x'
And these are obtained by solving \nabla<sup>2</sup>u+k2u=0 and looking for a and b based on the matching condition at x'. I'm wondering if I can do the same thing for this three dimensional case, using separation of variables and solving for k^2 as the eigenvalue. Then enforcing orthogonality on the functions I get. My problem with this is just that it seems very awkward to have eight sets of equation for the Green's function, based on whether x<x' while y>y' and z<z' for example.

Any help appreciated.
 
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I guess you could do that. You can always use Fourier transform to obtain the Green's function without BC and add a particular solution of the homogeneous Helmholtz equation that satisfies the BC instead, which I imagine would be a less awkward approach.
 
So using the Fourier transform would just give you the green's function for helmholtz in 3d space which is something like an exponential divided by 4∏r followed by simply any function satisfying the BC? So in a 1-d case:
Helmholtz Green's function + sinkx for x<x' or
Helmholtz Green's function +sink(x-L) for x>x'

Thanks for the help.
 

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