Green's Function using Laplace Transformation

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The discussion focuses on deriving the Green's Function for the differential equation x' + x = f(t) with the initial condition x(t=0,t')=0. The user proposes rewriting the equation in terms of the Green's function and suggests multiplying by f(t') to solve it. They arrive at the expression G(s) = (1/(s+1)) e^(-st') and conclude that G(t,t') = e^(-(t-t')) * U(t-t'). The user seeks confirmation on whether this is the correct Green's function and inquires about the system's response when f(t) = U(t-1), where U is the Heaviside step function. The discussion emphasizes the application of Laplace transformation in solving differential equations using Green's functions.
dspampi
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I was wondering if someone could help me go through a simple example in using Green's Function.

Lets say:
x' + x = f(t)
with an initial condition of x(t=0,t')=0;

Step 1 would be to re-write this as:
G(t,t') + G(t,t') = \delta(t-t')

then do you multiply by f(t')\ointdt' ?
which I would believe would give me:

s G(s) + G(s) = e^-st

and G(s) = \frac{1}{s+1} e^-st'
then giving me my G(t,t') = e^-(t-t') * U(t-t') ?

Not sure if that is the expected Green's function or if I screwed up somewhere.

Also, if f(t) = U(t-1), what would be the system's response?
* U fxn is a Heaviside step function
 
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