[Griffiths ex4.2] Electric field of a uniformly polarized sphere

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SUMMARY

The discussion focuses on the electric field produced by a uniformly polarized sphere, as outlined in Griffiths' section 4.2.1. It clarifies that while the volume charge density (ρ_b) is zero for a uniformly polarized sphere, the surface charge density (σ_b) is not uniform, leading to a non-zero electric field inside the sphere. The participants confirm that the polarized sphere can be treated as a combination of surface and volume charges, despite the misconception that uniform polarization implies uniform charge densities.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with Griffiths' "Introduction to Electrodynamics" (4th Edition)
  • Knowledge of Gauss's law
  • Concept of polarization and bound charges
NEXT STEPS
  • Study the derivation of electric fields from bound charges in polarized materials
  • Learn about the implications of non-uniform surface charge densities
  • Explore the mathematical treatment of electric fields in dielectric materials
  • Investigate the relationship between polarization (P) and bound charge densities (σ_b and ρ_b)
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Students and professionals in physics, particularly those studying electromagnetism, as well as educators teaching concepts related to electric fields and polarization in materials.

peguerosdc
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Homework Statement
Find the electric field produced by a uniformly polarized sphere of radius R
Relevant Equations
##\sigma_b = \boldsymbol{P} \cdot \boldsymbol{\hat{n}}##
##\rho_b = - \nabla \cdot \boldsymbol{P} ##
Hi!

This is more a conceptual question rather than the calculation itself.

So, Griffiths' section 4.2.1 "The field of a polarized object / Bound charges" says that if you want to calculate the field produced by a polarized material, you can find it from the potential of a surface charge and a volume charge like this:

## V(\mathbf{r}) = \frac {1} {4\pi\epsilon_0} \oint \frac {\sigma_b} {r - r'} da' + \frac {1} {4\pi\epsilon_0} \int \frac {\rho_b} {r - r'} d\tau' ##

which are called "bound charges".

As I understand this, it means that you can see the polarized object as a combination of two objects i.e. for the case of a polarized sphere of radius R, you can consider it as a shell of radius R with a surface charge density ##\sigma_b## and a solid sphere of radius R with volume charge density ##\rho_b## and use all the theory we already know for those cases i.e. Gauss's law (if useful), definition of E, etc.

Is this correct? The reason I ask (and the reason I suspect it is not) is because in example 4.2, Griffiths asks you to find the electric field produced by a uniformly polarized sphere of radius R, but as the sphere is uniformly polarized, then ##\rho_b=0##, so it should mean that I can consider the polarized sphere as only a spherical shell with charge density ##\sigma_b##, right?. If my assumption is correct, then the electric field inside the polarized sphere should be 0 (as it would be the field only due to the spherical shell) but NO! Griffiths says there is a non-constant potential inside the polarized sphere and, thus, a non-zero electric field inside.

Then, why is my assumption of making a polarized object a combination of surface + volume objects not correct if, apparently, from the equation of V it should?
 
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peguerosdc said:
The reason I ask (and the reason I suspect it is not) is because in example 4.2, Griffiths asks you to find the electric field produced by a uniformly polarized sphere of radius R, but as the sphere is uniformly polarized, then ##\rho_b=0##, so it should mean that I can consider the polarized sphere as only a spherical shell with charge density ##\sigma_b##, right?. If my assumption is correct, then the electric field inside the polarized sphere should be 0 (as it would be the field only due to the spherical shell) but NO! Griffiths says there is a non-constant potential inside the polarized sphere and, thus, a non-zero electric field inside.

Then, why is my assumption of making a polarized object a combination of surface + volume objects not correct if, apparently, from the equation of V it should?

The surface charge density is not uniform, so the field inside is not zero.
 
Following what @PeroK says, the surface bound charge density \sigma_b \neq \overrightarrow{(constant)}.
Why is this so? What is your definition of \sigma_b?
 
The definition is ##\sigma_b = \vec P \cdot \hat n = P \cos(\theta) ## so, right! It is not uniform so the field is not zero inside the sphere.

Such an obvious error, but lesson learned: if P is uniform, that doesn´'t mean the densities are going to be uniform. Thanks!

Besides from that, just to confirm, is my assumption that we can now consider the problem as a combination of surface + volume objects correct?
 
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peguerosdc said:
Besides from that, just to confirm, is my assumption that we can now consider the problem as a combination of surface + volume objects correct?

Yes, that's the whole point.
 

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