Group velocity and the dispersion relation

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SUMMARY

The discussion centers on the calculation of group velocity (Vg) in relation to phase velocity (v) and the dispersion relation. The derived expression for group velocity is Vg=(c/n)+0.6*c*lambda/n^2, where c represents the speed of light and n is the refractive index. Participants emphasize the importance of correctly applying the chain rule during differentiation and clarify that group velocity cannot exceed phase velocity. The relationship between group and phase velocity is also highlighted, noting that group velocity is associated with information transfer.

PREREQUISITES
  • Understanding of wave mechanics and dispersion relations
  • Familiarity with differentiation and the chain rule in calculus
  • Knowledge of phase velocity and group velocity concepts
  • Basic understanding of refractive index and its implications
NEXT STEPS
  • Study the derivation of the dispersion relation in wave mechanics
  • Learn about the implications of group velocity in information transfer
  • Explore the relationship between phase velocity and group velocity in different media
  • Investigate applications of group velocity in optics and telecommunications
USEFUL FOR

Students and professionals in physics, particularly those focusing on wave mechanics, optics, and telecommunications, will benefit from this discussion.

Kaguro
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Homework Statement
Q.Light of wavelength λ (in free space) propagates through a dispersive medium with refractive index n(λ)=1.5 + 0.6λ. The group velocity of a wave travelling inside this medium in units of 10^8 m/s is
(A) 1.5 (B) 2.0 (C) 3.0 (D)4.0
Relevant Equations
Group velocity is dw/dk. And phase velocity v is w/k.
After noting w=vk and differentiating with respect to k, and lots of simplifying, I get:

Vg = c/n +(2*pi*0.6)/(k*n)

This doesn't correspond to any numerical value though...
 
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You differentiated what with respect to k?
 
kuruman said:
You differentiated what with respect to k?
I differentiated both sides of the equation w=vk w.r.t k

This will give me
dw/dk=v + k(dv/dk)

Group velocity is then dw/dk.
v is c/n the phase velocity..

and then I wrote k=2*pi/lamda
And substituted value of dk.
 
It looks like you did not apply the chain rule correctly.
 
Last edited:
kuruman said:
It looks like you did not apply the chain rule correctly.
Oh! That's right...

Now the value I get for group velocity is:

Vg=(c/n)+0.6*c*lamda/n^2

Is this correct?

Even so, this is not a numerical answer..
 
Kaguro said:
Oh! That's right...

Now the value I get for group velocity is:

Vg=(c/n)+0.6*c*lamda/n^2

Is this correct?

Even so, this is not a numerical answer..
Look at your expression. It says that group velocity is equal to phase velocity plus something greater than zero. Can the group velocity be greater than the phase velocity? How did you get your answer. Please post the details of your work.
 
15817913115388635755890327047965.jpg


This is my work. Sorry for not typing all this out. That would have taken me hours..
 
The photo is upside down. Next time please post any photos right side up. It's the considerate thing to do.

Your final expression looks algebraically correct.
 
Last edited:
  • #10
A quick check is to remember that group velocity is related to information transfer, hence it is always less than or equal to the speed of light in vacuum. Phase velocity, on the other hand, does not convey any information and can be greater than c.
 

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