Gun and Shell: Calculate Velocity and Force

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SUMMARY

The discussion focuses on calculating the recoil velocity of a gun and the force required to stop it after firing a shell. Using the conservation of momentum, the recoil velocity of the gun is determined to be 2 m/s. The initial calculation for the stopping force yielded 8000 N, but the correct force, as per the book, is 4000 N. The discrepancy arises from an incorrect assumption about the constancy of velocity during the stopping process.

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Homework Statement


A gun of mass 500Kg fires a shell of mass 2Kg with a muzzle velocity of 500m/s.
Calculate:
i) the velocity of recoil of the gun
ii) the force required to stop the gun in a distance of 0.25m


Homework Equations





The Attempt at a Solution


i)I got the velocity of the gun by using the principal of conservation of momentum:
(500)(0) + (2)(0) = 500v + (500)(2). I got 2m/s.

ii)First i used v=d/t, 2=0.25/t, I got 0.125 seconds.
Then i used Force = change in momentum/time taken.
I get 8000N but the book says 4000N.
Im not sure what I am doing wrong??
 
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milan.007 said:
First i used v=d/t …

Hi milan!

You've assumed the velocity is constant (at 2 m/sec).

That gave you the wrong value of t.

Can you see some other way to calculate t (from initial velocity, final velocity, and distance)? :smile:
 

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