The discussion revolves around calculating the average recoil force experienced by a machine gun firing 50-gram bullets at a rate of 4 bullets per second, with each bullet leaving the gun at a speed of 1000 m/s. Participants are exploring the relationship between impulse, momentum, and force in this context.
Some participants have provided guidance on the correct application of formulas and units, while others are still grappling with the calculations and assumptions. There is an ongoing exploration of different interpretations of the problem setup and the equations involved.
Participants are navigating potential confusion regarding unit conversions and the time frame for the calculations, as well as the implications of using multiple bullets versus a single bullet in their reasoning.
Check that equation (J=mvt) by dimemsional analysis.gcombina said:J = ft
= (mv) t
No - it specifically asks for the average force of the recoil. $$\bar F = \frac{\Delta p}{\Delta t}$$* its asking me for the recoil which means the impulse right?
No, ##F=ma##.and that is J = ft and what is force? f = mv right?
Or just use one bullet averaged over 0.25s ... whatever, should get the same number.* mass is 200g because of the 4 bullets and velocity is 1000m/s
gcombina said:ok I did
F = Δp / Δt
but still I am getting the same bad answer
F = (200 gr/s) (1000 m/s) / (1s)
what is wrong with my equation?
Are you not expected to give Force in SI units?F = (200 gr/s) (1000 m/s) / (1s)