Gymnast Equilibrium: Tension Calc.

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SUMMARY

The discussion focuses on calculating the tension in the support ropes of a gymnast hanging stationary from two fixed rings. The gymnast has a mass of 65.0 kg, and the ropes make an angle of 5.0 degrees to the vertical. Using the equilibrium equation, the tension in each rope is calculated to be 320 N. This solution is confirmed as correct by participants in the discussion.

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[SOLVED] Gymnast equilibrium

Homework Statement


A gymnast of mass 65.0kg hangs from two fixed rings as shown in the diagram.
The gymnast is stationary and the support ropes make an angle of 5.0degrees to the vertical.

Calculate the tension in each of the support ropes.

http://img401.imageshack.us/img401/8334/gymnastpu6.jpg

Homework Equations


[tex] \sum {F_{up} } = \sum {F_{down} } [/tex]

The Attempt at a Solution


Well I have drawn a free body diagram.
Is this attempt correct?

[tex] \begin{array}{l}<br /> \sum {F_{up} } = \sum {F_{down} } \\ <br /> 2\left[ {T\cos 5} \right] = 65 \times 9.8 \\ <br /> \Rightarrow T = 3.20 \times 10^2 N{\rm} \\ <br /> \end{array}[/tex]
in each rope

Thanks in advance
Steven.
 
Last edited by a moderator:
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Absolutely.
 
thanks for clearing that up :)

Steven
 

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