A 60 kg tight-rope walker carries a long beam with a mass of 30kg accross a 10m long wire. When she is at the centre of the wire (i.e. 5 m across) each section of the wire makes an angle of 5 degrees to the horisontal. Calculate the tension in the wire.(adsbygoogle = window.adsbygoogle || []).push({});

This one is not that difficult but a lack a certain part of me to get the answer.

60+30 = 90 which is the combined weight Multiply this by 9.8 and we get the force the combined weight exerts on the wire. This is 882 Newtons. Now, from trigonometry i got the tension in the wire to be (2 * 882)/sin(5degrees) = 20239 Newtons of tension. This is 4 times the correct answer. So i though that maybe half the weight acts on half the wire to 822/sin(5degrees) might be the answer but it would leave you with double the correct answer. Argh.

I need help on this one :)

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# Homework Help: Transitional Equilibrium: Tension

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