A block of mass m1 = 290 g is at rest on a plane that makes an angle θ = 30° above the horizontal. The coefficient of kinetic friction between the block and the plane is µk = 0.10. The block is attached to a second block of mass m2 = 220 g that hangs freely by a string that passes over a frictionless and massless pulley. Find its speed when the second block has fallen 30.0 cm. cm/s What I have done: I turned the 2 masses into kg. M1 = .29kg and M2 = .22kg M1 Force of Gravity = .29kg * 9.81 m/s^2 = 2.8N M1 Normal Force = 28 * cos30 = 2.4N M1 Parallel Force = 28 * sin30 = 1.4N M1 Friction Force = .10 * 2.4 = .24N M2 Force of Gravity = 2.1N This where I am stuck, I don't know what I should do next to determine the speed of M2 when it is falling. Edit: The Net Force would be 1.4N - .24N = 1.16N = 2.1N - 1.16N = .94N F = M * A .94N = .51kg * A A = 1.8 m/s^2 Since there is 100 centimeters in a meter so A = 180 cm/S^2 Speed = Distance * Time X = 30cm * T Where T = 30/180 = .17s 30 * .17s Speed = 5.1cm/s Is this correct?