Halved volume with chemical equilibrium

[Walzf]

Homework Statement

The reaction is PCl5 (g) <=> PCl3 (g) + Cl2
In an unknow volume, the following mixture is balanced:
0.14 atm of PCl5
0.36 atm of PCl3
0.50 atm of Cl2

What would be the the pressure of the whole mixture if the volume would be halved?

(the answer is 1.88 atm)

Homework Equations

p1+p2+p3=1 atm
Kp=p3*p2/p1

The Attempt at a Solution

Since the answer is 1.88 atm I assumed the ideal gas laws aren't valid in this question because then the pressure would be 2 atm. I calculated Kp and it's 1.29 atm. But now I'm stuck.

 

[AGNuke]

1. If the ideal gas law isn't valid for this question, good luck then. Luckily, they are applicable. (Generally are, unless Van der waal's Gas is given.)

2. Since the system is disturbed, the equilibrium will shift so as to minimize the effect. Since the volume is halved or the pressure is doubled, the equilibrium will shift to decrease the pressure (Guess how?) But it can only do it to some extent.

Try gathering some relevant know-how on how to solve these types of problems (they are generally book illustrations).