The maximum "hang time" for a human who jumps in the air under his own power is said to be less than 1 second. This includes jumping on the spot, running jumps, hops, leaps, dives, and bounds. Javier Sotomayor (Cuba) is the current men's record holder with a jump of 2.45 m (8 ft 1⁄4 in) set in 1993. Using a stop watch, I timed it (see below) at less than 1 second. So it would appear that the 1 second rule holds in this case, and I'd wager even Michael Jordan couldn't stay in the air any longer. If H = 2.45 m, the total vertical distance would be 2H = 4.50 m. H = 1/2 gt^2, where g = 9.81 m/sec^2. So t = sqrt(2H/g) = sqrt(4.9/9.81) = 0.71 seconds. Still less than a second in the air! I did a bit of calculating and found that a person would have to execute a vertical leap of about 11 feet 4 inches (~16/sqrt2 feet) or 3.47 m (~4.9/sqrt2 meters) in order to stay off the ground for one second. This is the time elapsed from when the last part of your body leaves the ground to when the first part of your body touches down. Does anyone else get the same results?