(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A block of mass m rests on a horizontal table and is attached to a spring of force constant k. The coefficient of friction between the block and the table is mu. For this problem we will assume that the coefficients of kinetic and static friction are equal. Let the equilibrium position of the mass be x = 0. The mass is moved to the position x = +A, stretching the spring, and then released.

1 Apply Newton's 2nd law to the block to obtain an equation for its acceleration for the first half cycle of its motion, i.e. the part of its motion where it moves from x = +A to x < 0 and (momentarily) stops. Show that the resulting equation can be written d^2x'/dt^2 = -omega2 * x', where x' = x - x0 and x0 = mu*m*g/k. Write the expression for position of the block, x(t), for the first half cycle (be sure to express omega, the angular frequency, in terms of the constants given in the problem statement). What is the smallest value of x that the mass reaches at the end of this first half cycle?

2 Repeat the above for the second half cycle, i.e. wherein the block moves from its maximum negative position to its (new) maximum positive position. First show that the differential equation for the block's acceleration can be written d^2x''/dt^2 = -omega2*x'' where this time x'' = x + x0. Next, match the amplitude for the beginning of this half cycle with the amplitude at the end of the last one. Write the expression for the position of the block, x(t), for the second half cycle.

3 Make a graph of the motion of the block for the first 5 half cycles of the motion in the case where A = 10.5*x0. Plot the position of the block normalized to x0 as a function of the fractional period, T = 2*Pi/omega (i.e. plot x(t)/x0 vs t/T).

2. Relevant equations

3. The attempt at a solution

I got a half way down to the problem 1., i.e., i got an equation for d^x/dt^2

which is eqaul to -k/m(x-(mu*m*g)/k).

But I don't really get how to find a generic equation for position x(t).

If it were a mere simple harmonic motion, it might have been easy; x(t) = Acos(wt).

However, with a daming factor (mu*m*g)/k, I don't see any way to figure out a formula for position x(t).....

I'll be looking forward to your suggestions or ideas on this problem. Thank you!!

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# Homework Help: Harmonic motion whose damping is not related to velocity

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