Having some issues deriving internal force functions for a section.

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Discussion Overview

The discussion revolves around deriving internal force functions for a beam subjected to a triangular distributed load and a moment at one end. Participants are addressing issues related to shear and bending moment equations across different sections of the beam, focusing on the calculations and their correctness.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The beam is supported at two points and subjected to a triangular distributed load and a moment, leading to specific reaction forces calculated by the original poster.
  • The original poster expresses uncertainty about the bending moment equation for the section of the beam from 9 to 13 feet, noting a discrepancy in expected values.
  • One participant points out that there is zero shear for x > 9 and questions the meaning of the factor (x-3) in the bending moment equation.
  • The original poster attempts to clarify that (x-3) represents the distance from the distributed load to the resultant force but acknowledges confusion regarding its application.
  • Another participant requests to see all working to verify the reaction forces calculated by the original poster.
  • There are multiple mentions of the bending moment being expected to be -200 lb-ft from 9 to 13 feet, but the equations presented do not seem to reflect this correctly.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of the bending moment equations and the interpretation of certain terms. There is no consensus on the proper formulation of the bending moment for the section beyond 9 feet, and the discussion remains unresolved.

Contextual Notes

There are unresolved issues regarding the assumptions made in the calculations, particularly concerning the interpretation of shear and bending moment equations across the beam's length.

Bill Nye Tho
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Homework Statement



I have a 13 foot long beam supported by a pin at x = 0 feet and a roller at x = 9 feet.

There is a triangular distributed load of 50 lb/ft from 0 ft to 9 ft. (Increasing as it approaches 9 ft)

At the end of the beam there is a moment of 200 lb-ft counter-clockwise.

Homework Equations



ƩFx = 0
ƩFy=0
ƩMr = 200 lb-ft

Vertical Force at Pin: 52.78 lbs upward
Vertical Force at Roller: 172.22 lbs upward
Normal Force = 0

The Attempt at a Solution



For the first section, it seems my equations are correct;

0 < x < 9:

Shear: -.5(50/9)x^2 + 52.78
Bending: -.5(50/9)x^3/3 + 52.78x----

This is where I'm having an issue with my Bending equation;

9 < x < 13:

Shear: -225 + 52.78 + 172.22
Bending: 52.78x + 172.22(x-9) - 225(x-3)-----At exactly 9 feet, both bending functions should give a bending moment of -200 lb-ft but for some reason, I can't seem to get that answer with the second one. I tried to rework this function a few times but it's not happening.
 
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The applied couple (200 ft-lb) at the end of the beam (x = 13 ft) means there is a jump in the bending moment value at this location. However, for x > 9, there is zero shear. In your equations above, it's not clear what the factor (x-3) means, since the beam is 13 feet long and the right support occurs at x = 9 ft.
 
SteamKing said:
The applied couple (200 ft-lb) at the end of the beam (x = 13 ft) means there is a jump in the bending moment value at this location. However, for x > 9, there is zero shear. In your equations above, it's not clear what the factor (x-3) means, since the beam is 13 feet long and the right support occurs at x = 9 ft.

(x-3) is the distance of the resultant force (225 lbs) from the distributed load at any given point between 9 and 13 feet. <---- I think this is my problem. It makes no sense.

Since there is 0 shear after 9 feet, I'm just getting that the bending moment should be -200 lb-ft from 9 feet to 13 feet. This equation is not reflecting that though and I'm trying to figure out where I made my mistake. :(
 
Last edited:
I think I got it... I need some sleep

Bending Function: 52.78x + 172.22(x-9) - 225(x/3)
 
No ... I don't know what you mean by 225(x/3).

Also, what is 13 - 9 = ?
 
SteamKing said:
No ... I don't know what you mean by 225(x/3).

Also, what is 13 - 9 = ?

4, I can't believe I botched that up.
 
When you first calculated the reaction forces, did you check them by (say) taking moments about some axis not already used? You should show us all your working.
 

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