1. The problem statement, all variables and given/known data Force by uniform loading = 20(5) = 100kN Vertical component of the uniform loading = 20(5)(3/5) = 60kN Horizontal component of the loading = 20(5)(4/5) = 80kN vertical reaction at roller support = Vr vertical reaction at pin support = Vp 2. Relevant equations Fx=0, Fy=0, M=0 3. The attempt at a solution Finding reactions Horizontal reaction is only at pin support. Let it be Hp. As Fx=0 Hp=80-40=40kN (to the left) So I take moment at pin support first so as to find out Vr Vr=[40(1)+50(3)+60(7.5)-80(2)] / 9 = 160/3 kN (upwards) take moment at roller support to find Vp Vp=[100(2.5)+50(6)-40(1)] / 9 = 170/3 kN (upwards) Attempt to find out the equations for diagrams for the left part of the frame (free body) Resolving Vr into two component let the one perpendicular to frame be Rp, Rp = 32 kN the other one along the frame be Ra, Ra = 128/3 kN distance from roller be x Axial force = Ra = 128/3 kN Shear force = 32-20x, M=32x-10x2 But for the middle part and right part of the frame, how do I consider the free body? and the segments divided by the point loading? I tried thinking to cut at the top-right corner to consider the right part of the frame as a free body but then what should I do for the segment between the P2 loading and the corner? The middle part is even more messy to me. Thanks!