- #1

- 6

- 0

My attempt:

To calculate this I must use the format of V = ∏ ∫ y

^{2}dx. Thus I square the equation, giving me 81 / (2 - x)

^{2}.

Now I need to integrate the expression. Here is where I think I'm going wrong...expand the bottom term to get x

^{2}- 4x + 4.

I then try to integrate this expansion, getting 81 / (2x - 4) ln |x

^{2}- 4x + 4|.

This gives me the final equation of V = ∏ [81 / (2x - 4) ln |x

^{2}- 4x + 4|] from x = 0 to x = 1

Long story short I don't come to the right answer after all of that. I'm pretty sure I'm missing something easy and obvious. Please help!