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Having Trouble With an Intergration Problem

  1. Oct 2, 2013 #1
    I am given that the equation of a curve is y = 9 / (2 - x). They then ask me to find the volume obtained by the region bounded by the curve, the coordinate axes and the line x = 1 when the region is rotated through 360° about the x-axis.

    My attempt:

    To calculate this I must use the format of V = ∏ ∫ y2 dx. Thus I square the equation, giving me 81 / (2 - x)2.

    Now I need to integrate the expression. Here is where I think I'm going wrong...expand the bottom term to get x2 - 4x + 4.
    I then try to integrate this expansion, getting 81 / (2x - 4) ln |x2 - 4x + 4|.

    This gives me the final equation of V = ∏ [81 / (2x - 4) ln |x2 - 4x + 4|] from x = 0 to x = 1

    Long story short I don't come to the right answer after all of that. I'm pretty sure I'm missing something easy and obvious. :frown: Please help!
  2. jcsd
  3. Oct 2, 2013 #2


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    You didn't integrate that correctly at all. Use the substitution u=(2-x). What's the integral of 1/u^2=u^(-2)???
  4. Oct 2, 2013 #3


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    Your method of obtaining the volume is incorrect.

    Review the Second Theorem of Pappus:
  5. Oct 2, 2013 #4


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    I see no problem with the formulation of the integral, but as Dick notes, the algebra went awry from there.
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