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**1. The problem statement, variables and given/known data**

A tourist being chased by an angry bear is running in straight line toward his car at a speed of 4.0m/s. The car is a distance d away. The bear is 26m behind the tourist and running at 6.0m/s. The tourist reaches the car safely. What is the maximum possible value for d?

## Homework Equations

V = Vo + at

X = 1/2(Vo + V)t

X = Vo * t + 1/2at^2

V^2 = Vo^2 + 2ax

Vo is initial velocity

V is final velocity

a is acceleration

x is distance

## The Attempt at a Solution

I'm honestly stumped on this question. I know the objective is to find the max amount possible for d(or x) to be for the man to get to his car safely.