Train deceleration and minimum stopping distances

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Homework Help Overview

The discussion revolves around the deceleration of two trains and the calculation of their minimum stopping distances. Participants are exploring the implications of their calculations and the relationships between the distances and times involved in stopping.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of acceleration and displacement formulas to determine stopping distances. There are questions about the correctness of calculations and the rationale behind certain steps, such as subtracting distances. Some participants also question the notation used for velocity direction.

Discussion Status

The conversation is ongoing, with participants sharing their calculations and questioning each other's approaches. There is an exploration of different methods to arrive at the same conclusion, and some participants express uncertainty about their reasoning and the implications of their results.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available and the methods they can use. There is a focus on ensuring that the calculations align with the problem's requirements and assumptions.

lol2
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Homework Statement
Two trains are traveling on the same linear track but in opposite direction and toward each other. The train on the right is moving to the left with a velocity of 54 m/s and the train on the left is moving to the right with a velocity of 38 m/s. When the brakes are fully applied on the train on the right, the ensuing acceleration has a magnitude of 0.31 m/s2.

Given the trains have their breaks applied simultaneously and come to a stop at exactly the same instant,
--determine the minimum distance between the trains at which they could fully apply their brakes and come to a complete halt without colliding.
--determine the acceleration of the train on the left.
Relevant Equations
x= 1/2at^2+Vot+Xo
a= delta v/t
So my work includes using the acceleration formula a=delta v/t

(Vrtf-Vrti)/a -> (0-54)/(-0.31) -> t=174 seconds

I plug in 174 seconds to find the acceleration of the left train. and got -0.22m/s^2

I then used the displacement equation
x=(1/2)at^2+Vo+So
coming out with Xrt=4703m and Xlt= 3281m

I subtracted those coming out with 1422m, which is the minimum distance between each train to safely halt without crashing.

is that right?!
 
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The answer I came up with for ##distance_{initial}## (through a slightly different route that didn't include calculating the time because it isn't required) is the same as the answer you'll come up with if you doublecheck your signage.
 
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what was the route you took?
 
lol2 said:
I subtracted those
Umm... why?
 
haruspex said:
Umm... why?

it seemed like the good option... I'm guess that wasn't the right pathway :/
 
lol2 said:
it seemed like the good option... I'm guess that wasn't the right pathway :/
If the first train takes about ##4.7km## to stop and the second train takes about ##3.3 km## to stop, then what happens if they start about ##1.4 km## apart?
 
While we're at it, in part one, is "##-##" the correct notation for the direction of the velocity ? given the wording of the question.
 
lol2 said:
it seemed like the good option... I'm guess that wasn't the right pathway :/
When in doubt, draw a picture.
1590694827873.png
 
PeroK said:
If the first train takes about ##4.7km## to stop and the second train takes about ##3.3 km## to stop, then what happens if they start about ##1.4 km## apart?

*CRASH*
 

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