Heat Absorbed Changing 2kg Ice to Steam: Calculation

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    Thermodynamics
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SUMMARY

The calculation of heat absorbed in changing 2 kg of ice at -5°C to steam at 110.0°C involves multiple steps using specific heat capacities and phase change enthalpies. The specific heats are 2060 J/kg·K for ice, 4180 J/kg·K for water, and 2020 J/kg·K for steam. The heat of fusion is 3.34 x 10^5 J/kg, and the heat of vaporization is 2.26 x 10^6 J/kg. By applying these values systematically, one can determine the total heat absorbed during the transformation.

PREREQUISITES
  • Understanding of specific heat capacity
  • Knowledge of phase changes and associated enthalpies
  • Familiarity with the formula for calculating heat transfer (Q = mcΔT)
  • Basic thermodynamics principles
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  • Calculate heat absorbed during phase changes using specific heat capacities
  • Explore detailed examples of heat transfer calculations in thermodynamics
  • Study the implications of heat fusion and heat vaporization in real-world applications
  • Learn about the laws of thermodynamics and their applications in energy transfer
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Students in physics or chemistry, educators teaching thermodynamics, and professionals involved in energy systems or heat transfer calculations.

panther7
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How much heat is absorbed in changing 2-kg of ice at -5°C to steam at 110.0°C? The Specific heats of ice, liquid water, and steam are, respectively, 2060 J/Kg x K, 4180 J/Kg x K, and 2020 J/Kg x K. The heat fusion of ice is 3.34 x 10^5 J/Kg. The heat of vaporization of water is 2.26 x 10^6 J/kg
 
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