Heat Capacity of Air at Constant Volume

[s.p.q.r]

Hi

I have an ongoing dispute with my mate on this one, please help to clarify this before I open up a can of whoop ass on that sorry mo-fo.


300 litres of air are compressed into a 3 litre tank. What is the heat capacity of this air?

Thanks in advance.

 

[Hootenanny]

What do you think it is?

 

[s.p.q.r]

The Cp J mol is 29.19. But because I ask for constant volume, it is definitely lower then this. This is what I think. I can find no references to constant volume anywhere and unfortunately I have no teacher to ask as I study archaeology, not physics.

Do you have the answer?


Thanks in advance.

 

[Andrew Mason]

The Cp J mol is 29.19. But because I ask for constant volume, it is definitely lower then this. This is what I think. I can find no references to constant volume anywhere and unfortunately I have no teacher to ask as I study archaeology, not physics.

Do you have the answer?Thanks in advance.

Air is almost entirely a diatomic gas, \gamma = C_p/C_v = 1.4 (7/5)

AM

 

[s.p.q.r]

Hi,


Thanks for the reply. Is 1.4 per gram or mol?

Also,

How can you measure a gram of gas and how much is 1 mol?

Cheers.

 

[mgb_phys]

1.4 is a ratio ( actually nearer 1.3 for dry air at room temp)
see http://en.wikipedia.org/wiki/Heat_capacity_ratio
1 mol of air is roughly 30g or 22.4litres at STP ( 0deg C 1 atm)

 

[Loren Booda]

Is heat capacity independent of volume for an ideal gas?

Stupid question - gas performs work while being compressed.

 

[mgb_phys]

For an ideal gas heat capcity just depends on the amount (number of moles) present and the number of vibration states of the molecular.
For a real gas it also depends on the pressure because the molecules close to each other change the vibration state/bond energy.

 

[Loren Booda]

In a modification of the "ideal gas" law, I seem to recall an equation with correction terms for the volume and pressure, respectively. Has anyone run across this?

 

[s.p.q.r]

Hi,
This ratio of 1.4, does this just mean that you divide the constant pressure capacity (1.020J/g) by 1.4?

 

[Andrew Mason]

Hi,
This ratio of 1.4, does this just mean that you divide the constant pressure capacity (1.020J/g) by 1.4?

\gamma = 1.4 is the ratio of the specific heat (heat flow per gram or per mole per degree K change in temperature) at constant pressure to the specific heat at constant volume. \gamma = C_p/C_v. What you want to find is Cv. You also have to find the number of moles of air in this container to find its heat capacity (heat flow per degree K change in Temp.).

AM