Heat equation on a half line: Techniques for Solving and Verifying Solutions

Click For Summary
SUMMARY

The discussion focuses on solving the heat equation on a half line, specifically addressing the challenges posed by boundary conditions at x=0 and infinity. Participants highlight that while the sine transformation is commonly referenced, it results in a solution of zero at x=0 due to the odd function assumption. Alternative techniques such as the Laplace transform and heat kernel methods are suggested for more accurate solutions. The need for clarity in the specific problem context is emphasized to facilitate effective problem-solving.

PREREQUISITES
  • Understanding of the heat equation and its boundary conditions
  • Familiarity with Laplace transforms and their applications
  • Knowledge of heat kernel methods for solving differential equations
  • Basic principles of Fourier decomposition and its relevance to heat flux
NEXT STEPS
  • Research the application of Laplace transforms in solving partial differential equations
  • Explore heat kernel techniques for the heat equation on bounded domains
  • Study Fourier decomposition methods for time-dependent boundary conditions
  • Investigate the verification of solutions for initial and boundary conditions in differential equations
USEFUL FOR

Mathematicians, physicists, and engineers dealing with heat transfer problems, particularly those focused on solving differential equations with specific boundary conditions.

jollage
Messages
61
Reaction score
0
Heat equation on a half line!

Hi,

I am now dealing with the heat equation on a half line, i.e., the heat equation is subject to one time-dependent boundary condition only at x=0 (the other boundary condition is zero at the infinity) and an initial condition.

I searched online, it seems that for the half line problem, only the sine transformation can solve the heat equation, but in that case, the final result is always zero at x=0 since when doing sine transformation, one should assume that the to-be-transformed function is odd, so the function is zero at x=0.

My question is, do you know any other techniques to solve the heat equation on the half line without using sine transform?

Thanks.
 
Science news on Phys.org
Sinusoidally varying temperatures don't really make sense. Try using the Laplace transform.
 
What is the specific problem?
 
jollage said:
I searched online, it seems that for the half line problem, only the sine transformation can solve the heat equation, but in that case, the final result is always zero at x=0 since when doing sine transformation, one should assume that the to-be-transformed function is odd, so the function is zero at x=0.

IF you tell us where you got that (wrong) idea, we might be able to explain what the website means, or confirm that it really is wrong.

mikeph said:
Sinusoidally varying temperatures don't really make sense. Try using the Laplace transform.

Sinusoidal in time, or in space? For example if you were applying a heat flux at x = 0 which was a periodic function of time, it would make good sense to do a Fourier decomposition of it.

As Chestermiller said, posting the complete problem would help.
 
Fourier, yes, decomposing it into sine waves, not so much. You need those exponential decays to make it die at infinity.
 
Hi,

Thanks for all your replies!

I didn't say it's sinusoidal, it's just a time-dependent function, not periodic.

Sorry, I shouldn't say "only the sine transformation can solve the heat equation". Yesterday, I just found using heat kernel can also solve the problem on a half line.

The document I upload is the note I took. I have a problem. When I tried to verify the solution by checking the initial condition and boundary condition, I have some problem to see the solution can really give initial condition, i.e., to set t=0 in the equation 18 of the document. I know one should take the limit as t->0+, but I failed to reach that. Do you have any clue?

Thanks!
 

Attachments

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K