- #1

Amith2006

- 427

- 2

A man covers his body with a blanket of thickness 4 mm. His temperature is 37 degree Celsius and that of the atmosphere is 27 degree Celsius. If the coefficient of thermal conductivity of wool is 1.2 x 10^(-5) W/m.K , what is the heat lost per hour per square meter area?

I solved it in the following way:

Heat loss = KA(T1 – T2)t/y

Here K = 1.2 x 10^(-5) W/m.K

T1 – T2 = 10 K

y = 4 x 10^(-3)

Heat lost per unit area per hour = [1.2 x 10^(-5) x 10 x 3600]/(4 x 10^(-3))

= 108 Joule

Is it right?