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Homework Help: Heat loss per unit area per hour

  1. May 27, 2006 #1
    Sir,
    A man covers his body with a blanket of thickness 4 mm. His temperature is 37 degree Celsius and that of the atmosphere is 27 degree Celsius. If the coefficient of thermal conductivity of wool is 1.2 x 10^(-5) W/m.K , what is the heat lost per hour per square meter area?
    I solved it in the following way:
    Heat loss = KA(T1 – T2)t/y
    Here K = 1.2 x 10^(-5) W/m.K
    T1 – T2 = 10 K
    y = 4 x 10^(-3)
    Heat lost per unit area per hour = [1.2 x 10^(-5) x 10 x 3600]/(4 x 10^(-3))
    = 108 Joule
    Is it right?
     
  2. jcsd
  3. May 27, 2006 #2

    Andrew Mason

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    Science Advisor
    Homework Helper

    Your explanation of what you are doing and your units is not clear. If you are clear on the physics of what you doing, the correct answer will be much easier to see.

    Heat conduction is given by:

    [tex]dQ/dt = \frac{\kappa A(T_1 - T_2)}{d}[/tex]

    where dQ/dt is the rate of heat transfer through the conducting material. You are looking for dQ/dt per unit area. So:

    [tex]\frac{1}{A}\left(\frac{dQ}{dt}\right) = \frac{\kappa (T_1 - T_2)}{d}[/tex]

    That will give you the answer in watts/m^2 or Joules/m^2 sec

    You are looking for Joules/m^2hour = (Joules x 3600)/m^2(3600 sec).

    So the answer is 108 Joules/m^2

    AM
     
    Last edited: May 27, 2006
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