Heat transmitted in convection from a pipe

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Homework Help Overview

The discussion revolves around heat transfer by convection from a vertical steam pipe with a specified temperature and surrounding air conditions. Participants are examining the calculation of heat delivered to the air through natural convection and the associated coefficients.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the heat convection current using a specific formula but questions the accuracy of their final result compared to a reference value. Other participants raise concerns about the use of certain values in the calculations and suggest re-evaluating the approach. Additionally, another participant shares a related problem regarding heat loss in steam pipes and the challenges faced in determining the heat transfer coefficient due to high Reynolds numbers.

Discussion Status

The discussion includes attempts to clarify calculations and identify potential errors in the original poster's approach. Some participants are exploring different scenarios of heat transfer, while others are questioning the applicability of certain equations based on the conditions described. There is no explicit consensus on the correct approach or solution at this stage.

Contextual Notes

Participants are dealing with specific constraints related to the physical setup of the steam pipes, including temperature differences and environmental conditions. The discussion also highlights the limitations of certain equations based on the calculated Reynolds number, which exceeds the valid range for some formulas.

Karol
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Homework Statement


A vertical steam pipe of outside diameter 7.5 cm and height 4 m has its outer surface at the constant temperature of 950C. The surrounding air is at atmospheric pressure and at 200C.
How much heat is delivered to the air by natural convection in 1 hr?

Homework Equations


\mbox{The heat convection current H: }H=hA\,\Delta t
\mbox{Coefficient of naural convection in air at atmospheric pressure for a vertical pipe (diameter D): }h=1.00\times10^{-4\left(\frac{\Delta t}{D}\right)^{1/4}}

The Attempt at a Solution


h=1.00\times10^{-4\left(\frac{75}{7.5}\right)^{1/4}=0.00018
H=0.00018\cdot\frac{\pi\cdot 7.5^2}{4}400\cdot 75=235.7\left[Cal/Sec\right]=848,469\left[Cal/hr\right]
The answer, according to the book, should be 454,000.
If this isn't the place for this subject, please guide me to another sight that deals with those kind of problems.
 
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I see you have '400' in your final line. I don't think that belongs there, else you are essentially multiplying by volume and not cross-sectional area 'A'.
 
I have a similar question. I'm trying to determine the heat loss in our steam pipes both outside exposed to the wind(forced convection) and inside our plant(free convection). I'm having some trouble in determining the heat transfer coefficient, h for both situations. When I calculate the Reynold's number for the wind blowing on the pipes, its so large that I can't use any of the normal equations to find the Nusselt number. The equations I'm using are
Nu = hl/k where h is heat transfer coefficient, l is a characteristic length (I'm using the diameter of the pipe and insulation), and k is the thermal conductivity of the insulation.
and
Nu = .023Re^.8 * Pr^.3 this range is valid for approx 100< Re < 50,000
My Re is 300,000+

Suggestions?
Thanks
 
cmpersson said:
I have a similar question. I'm trying to determine the heat loss in our steam pipes both outside exposed to the wind(forced convection) and inside our plant(free convection). I'm having some trouble in determining the heat transfer coefficient, h for both situations. When I calculate the Reynold's number for the wind blowing on the pipes, its so large that I can't use any of the normal equations to find the Nusselt number. The equations I'm using are
Nu = hl/k where h is heat transfer coefficient, l is a characteristic length (I'm using the diameter of the pipe and insulation), and k is the thermal conductivity of the insulation.
and
Nu = .023Re^.8 * Pr^.3 this range is valid for approx 100< Re < 50,000
My Re is 300,000+

Suggestions?
Thanks

you should start your own thread, but your Re is outside the range for that equation, thus it cannot be used for your problem.
 

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