Height of Pendulum Homework: A&B Answered, C&D Yet to Solve

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SUMMARY

The discussion focuses on calculating the heights reached by two spheres after elastic collisions in a two-sphere arrangement. Sphere 1, with a mass of 51 g and an initial height of 10 cm, collides elastically with sphere 2, which has a mass of 82 g. The equations used include Sqrt(2gh) for velocity and ((m1-m2)/(m1+m2))v for the velocity after collision. The user successfully calculated the heights for parts A and B but seeks assistance for parts C and D regarding the subsequent heights after the next collision.

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Homework Statement


In the two-sphere arrangement of Figure, assume that sphere 1 has a mass of 51 g and an initial height of 10 cm, and that sphere 2 has a mass of 82 g. After sphere 1 is released and collides elastically with sphere 2, what height is reached by (a) sphere 1 and (b) sphere 2? After the next (elastic) collision, what height is reached by (c) sphere 1 and (d) sphere 2?

I found A and B but not sure how to find c and d?

Homework Equations

The Attempt at a Solution



Sqrt(2gh)= v

((m1-m2)/(m1+m2))v=v1
(v1^2)/(2g)=H1

[/B]
 
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Since you have not attached the figure, you will need to describe the arrangement.
 

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