Heisenberg Uncertainty, Need Some Clarification. TIME SESITIVE, HELP

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Homework Help Overview

The discussion revolves around the Heisenberg uncertainty principle, specifically calculating the uncertainty in position (Δx) for a ball with given mass and velocity. The original poster expresses urgency in resolving their confusion regarding the calculation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the Heisenberg uncertainty principle but questions their approach after receiving an unexpected result. Some participants question the necessity of including the diameter of the ball in the calculation and suggest reconsidering the relationship used in the uncertainty principle.

Discussion Status

Participants are actively engaging with the original poster's calculations, providing feedback and raising questions about the assumptions made. There is a recognition of the potential for multiple interpretations of the uncertainty principle, and some guidance has been offered regarding the relationship used for the calculations.

Contextual Notes

The original poster is under time constraints, indicating a need for prompt assistance. There is uncertainty about the correct application of the uncertainty principle and the relevance of the diameter in the calculations.

asl3589
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Heisenberg Uncertainty, Need Some Clarification. TIME SESITIVE, HELP!

Homework Statement


Use the Heisenberg uncertainty principle to calculate Deltax for a ball (mass = 100 g, diameter = 6.65 cm) with Deltav = 0.645 m/s.


Homework Equations



PX = h/(4*3.14)

The Attempt at a Solution



So, I took the equation and converted the values with my
numbers:((h/4π)/(.1kg * .645 m/s))/(.0665m) and yielded an
answer. The answer I got with these numbers is 1.23 *
10^-32 m. This answer is wrong and I am not sure why. I only have two hours left to answer this question. I would really appreciate it if someone could guide me on what my mistake is?
 
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Hello asl3589,

Why did you divide by the diameter of the ball? :confused:

[Edit: Also, you seem to be using the more formal [tex]\sigma _x \sigma _p \geq \frac{\hbar}{2}[/tex] where [tex]\hbar = \frac{h}{2 \pi}[/tex]. But keep in mind that relationship is not an equality. If you want an approximate value with a [tex]\approx[/tex] sign and using [tex]\Delta x[/tex] and [tex]\Delta p[/tex], there is a slightly different version of the relation.]
 
Last edited:


Thanks for looking at it. I just assumed that the diameter factors into somehow. Is that unneccesary. If I take that step out the answer is just 8.174 * 10^-34 m. Is that right?
 


asl3589 said:
Thanks for looking at it. I just assumed that the diameter factors into somehow. Is that unneccesary. If I take that step out the answer is just 8.174 * 10^-34 m. Is that right?

That would give you the minimum possible uncertainty in position. But that's not necessarily the approximate uncertainty. The minimum possible uncertainty in position might be the answer your instructor is looking for, but I'm uncertain about that.
 

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