Helicopter Lift Force Calculation

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SUMMARY

The discussion focuses on calculating the lift force exerted by a helicopter lifting a 1250 kg car while accelerating upward at 0.545 m/s². The correct approach involves considering both the gravitational force and the upward acceleration. The formula for net force is clarified as F = ma + mg, leading to the conclusion that the lift force equals the tension in the cable plus the force required for upward acceleration. The final lift force can be computed using the equation F_h = m(a + g), where g is the acceleration due to gravity (9.8 m/s²).

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational force calculations
  • Familiarity with basic physics concepts of force and acceleration
  • Ability to manipulate algebraic equations
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  • Calculate lift force using F_h = m(a + g) with specific values
  • Explore tension in cables and its relation to forces in physics
  • Study the effects of acceleration on forces in dynamic systems
  • Review helicopter aerodynamics and lift generation principles
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Aerospace engineers, physics students, and anyone interested in understanding the dynamics of helicopter lift and force calculations.

strugglin-physics
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A 7850 kg helicopter accelerates upward at 0.545 m/s^2 while lifting a 1250 kg car. What is the lift force exerted by the air on the rotors?

What is the tension in the cable ignoring its mass that connects the car to the helicopter?

Net Force = ma, so I did (7850)(0.545) + (1250)(0.545) = 4959.5 N but that answer is incorrect and I know if I don't have the right answer for the first one I will not be able to solve the second one.

Would appreciate someone's assistance, thank you.
 
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I think you left out gravity!
 
Maybe you are correct... hmm... but where would I include it in this formula... Net Force = ma?
 
The total acceleration will be the acceleration due to gravity plus the acceleration produced by the helicopter.
 
so you're say that my a should equal .545 + -9.8 giving me an answer of -84221?
 
Let me state that a little more clearly. The net force acting on the car is the sum of the gravitational force and the force due to the helicpopter:
\vec F = \vec F_g + \vec F_h = m \vec a
so the force excerted by the helicopter is
\vec F_h = m \vec a - \vec F_g
Now gravity pulls downward (i.e. it's negative) so the net force in the vertical direction is F = ma - (-mg) = m(a+g) which is also the tension on the cable.
 
I'm feeling rather dumb as I still don't know what the lift force exerted by the air on the rotors is, but I do appreciate your attempt to help me understand. Maybe the solution will come to me...

Thanks again.
 
The lift force exerted on the air will be equal to the tension on the cable plus the force required to accelerate the helicopter upward!
 
Duh... now that seems pretty obvious! Thank you.
 

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