- #1
- 13
- 0
Hello, can anyone tell me how I can show that this diverges
[tex]\int_{-1}^0\frac{e^x}{x+1}dx[/tex]
I'm out of ideas
[tex]\int_{-1}^0\frac{e^x}{x+1}dx[/tex]
I'm out of ideas
neom said:Hello, can anyone tell me how I can show that this diverges
[tex]\int_{-1}^0\frac{e^x}{x+1}dx[/tex]
I'm out of ideas
neom said:Hello, can anyone tell me how I can show that this diverges
[tex]\int_{-1}^0\frac{e^x}{x+1}dx[/tex]
I'm out of ideas
homeomorphic said:As a warm-up, why does the integral of 1/x from 0 to 1 diverge?
It's not too different from that. Maybe use the comparison test, since you can bound e^x from below by some number greater than zero.
vikiabst said:integral -1 to 0 (e^x)/1+x>e^-2[integral -1 to 0 1/(1+x)]
The second term diverges so first term diverges.