Hello,The pseudoinverse formula for a matrix A is given by:P =

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The pseudoinverse formula for a matrix A is defined as P = (A^{T}A)^{-1}A^{T}. The existence of (A^{T}A)^{-1} is guaranteed when A is an nxk matrix with rank k, making ATA an invertible kxk matrix. In cases where A is degenerate, such as A = [[1, 1], [0, 0]], the pseudoinverse still serves as a left-inverse, functioning effectively for matrices that lack traditional inverses.

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Hello,

The pseudoinverse formula for a matrix A is given by:

P = (A^{T}A)^{-1}A^{T}

I remember knowing this some time ago and this has me worried now...why is (A^{T}A)^{-1} guaranteed to exist? I know it is a square matrix but it could still be degenerate, right?

Would appreciate any help.

Thanks,
Luca
 
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it's not guaranteed to exist.

for example, consider A =

[1 1]
[0 0].

the (left) pseudoinverse is useful when you have an nxk matrix (n > k) of rank k. then ATA is an invertible kxk matrix, so

(ATA)-1AT acts as a left-inverse (to the left-identity) for A, as you can easily verify by computation.

(in this case, In is merely a left-identity for the nxk matrices, the right-identity is Ik, and these matrices are of different sizes).

in other words, the pseudo-inverse "acts" like an inverse on a class of matrices which don't have inverses.
 
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