How Do You Calculate Angle and Velocity in Particle Motion Analysis?

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The discussion centers on calculating the position, velocity, and angle of a particle moving in the xy-plane, given its position function. Participants express confusion about the concept of "unit notation" and the necessary equations for converting from rectangular to polar coordinates. There's an emphasis on understanding the relationship between position and velocity in particle motion analysis. Additionally, the importance of demonstrating effort in homework questions is highlighted to receive effective assistance. The conversation underscores the need for clarity in mathematical terminology and the application of relevant equations.
Daretodaredar
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Homework Statement


the position "r" of a moving particle moving in an xy plane is given by r=(2.00(t^3) -5t)î+ (6.00-7.00(t^4) )j with r in meters and t in seconds. In unit notation calculate:
A) R
B) Velocity
C) R when t is 25 seconds
What is the able between the positive direction of the x-axis and a line tangent to its path at t=25 s


Homework Equations



I have no clue what to do!

The Attempt at a Solution

 
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Daretodaredar said:

Homework Statement


the position "r" of a moving particle moving in an xy plane is given by r=(2.00(t^3) -5t)î+ (6.00-7.00(t^4) )j with r in meters and t in seconds. In unit notation calculate:
A) R
B) Velocity
C) R when t is 25 seconds
What is the able between the positive direction of the x-axis and a line tangent to its path at t=25 s


Homework Equations



I have no clue what to do!

The Attempt at a Solution


Welcome to the PF.

What is "unit notation"?

And surely in the Relevant Equation section, you could list the method for converting from rectangular to polar notation, since you are asked to find an angle. And what is the relationship between the position R(t) and the velocity V(t) in general?

You need to show some effort on your schoolwork questions, if you want to receive tutorial help here.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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