Help calculating decibel level from intensity of sound

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To calculate the decibel level from sound intensity, the formula dB = 10 * log(I / 1.0 x 10^-12 W/m2) is used. For an intensity of 1.0 x 10^-5 W/m2, the correct calculation yields 70 dB. Users expressed confusion about inputting the equation into a calculator, particularly those unfamiliar with logarithmic functions. A simpler approach noted is recognizing that 10(12 - 5) equals 70. Overall, the discussion highlights the challenges faced by beginners in physics and calculator use.
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Homework Statement



Determine the decibel rating of the following intensities of sound.

I = 1.0 x 10-5 W/m2

Homework Equations



The equation which relates the intensity of a sound wave to its decibel level is:

dB = 10 * log( I / 1.0 x 10-12 W/m2)

The Attempt at a Solution



dB = 10 * log( 1 x 10-5 W/m2 / 1.0 x 10-12 W/m2) = ?

I put it into my calculator and can't actually get an answer out of it. I know the answer is 70dB as I looked in the answer booklet but I couldn't get that answer by entering the equation into it?

Any help would be greatly appreciated. Thanks
 
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It's right there, 10(12 - 5)=70 by inspection.
 
Doug Huffman said:
It's right there, 10(12 - 5)=70 by inspection.
Thankyou. How would this one be worked out? I am very new to physics so equations are confusing at the moment:

dB = 10 * log( 6.1 x 10-6 W/m2 / 1.0 x 10-12 W/m2) = 68 dB

How would that be inputted into a calculator?

Thank you very much :)
 
LOL Sorry, I haven't used a calculator in many years.

My collection of calculators (HP-35, 41, 48) live in the same box with a half-dozen slide rules.
 
Doug Huffman said:
LOL Sorry, I haven't used a calculator in many years.
No worries. Thank you for your help!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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