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Homework Help: Help concerning a simple operation

  1. Oct 3, 2013 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations

    3. The attempt at a solution

    Consider the equation

    [tex]1+A = (\sqrt{1 - B})^{-1}[/tex]

    A and B are just arbitrary constants.

    If I wanted to square both sides, would that be

    [tex]2 + A^2 = \frac{2}{1 - B}[/tex]

    or do I ignore the 1's and write it as

    [tex]1 + A^2 = \frac{1}{1 - B}[/tex]

    Thanks! I am just young and wanted to know!
    Last edited: Oct 3, 2013
  2. jcsd
  3. Oct 3, 2013 #2
    can anyone help me please?
  4. Oct 3, 2013 #3


    User Avatar
    Gold Member

    "Bumping" a thread in less than 24 hours is against forum rules. You should read the rules.

    You math is all completely wrong. I have no idea how you got ANY of what you got.

    EDIT: show the steps in how you got from one form to the next so we can see where you are going wrong.
    Last edited: Oct 3, 2013
  5. Oct 3, 2013 #4
    well isn't

    (something)^-1 = 1/(something)

    or do you mean how we arrive at the first formula? That isn't important, there isn't a derivation, it's just an equation.
  6. Oct 3, 2013 #5
    The right hand side of your final equation is correct, but the left hand side isn't.
  7. Oct 3, 2013 #6


    User Avatar

    Staff: Mentor

    OP is a sockpuppet of a previously banned crackpot.
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