Help converting complex number to cartesian

Click For Summary

Homework Help Overview

The discussion revolves around converting a complex number into Cartesian form and sketching it on an Argand diagram. Participants are exploring the relationship between the real and imaginary parts of the complex number.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss expressing the complex number in terms of real variables x and y, leading to equations that relate these variables. There are attempts to manipulate these equations to find relationships between x and y.

Discussion Status

Some participants have provided guidance on manipulating the equations and exploring relationships between the variables. There is an ongoing exploration of different algebraic manipulations, with no explicit consensus on a single approach yet.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for solving the equations. There is a focus on understanding the relationships rather than arriving at a final solution.

meee
Messages
87
Reaction score
0
how convert dis to cartesian form!?
quation was here
and then i will need to sketch on an argand diagram.
help apreciated thnx
 
Last edited:
Physics news on Phys.org
I'm not sure what you mean, but how about replacing z with x+iy and then write out the equation in terms of x and y.
 
ok... { x+yi: x + y = x*y }

like dat?
 
meee said:
ok... { x+yi: x + y = x*y }

like dat?
Indeed, now you found a relation between x and y, the real and imaginary part. You can even solve this for either x or y. So you're looking for all the complex numbers which satisfy this relation.
 
yea i don't kno, don reli get it... cud i do dis?

and then divide by xy...
1/x + 1/y = 1

= x + y = 1

= x^2 + y^2 = 1
 
meee said:
1/x + 1/y = 1
x + y = 1
What happens in this step?

I'd say:

[tex]xy = x + y \Leftrightarrow xy - y = x \Leftrightarrow y\left( {x - 1} \right) = x \Leftrightarrow y = \frac{x}{{x - 1}} = 1 + \frac{1}{{x - 1}}[/tex]
 
howd u do that last step?
 
meee said:
howd u do that last step?
That one isn't necessary, I split the fraction (by doing the division or manipulating the fraction):

[tex] y = \frac{x}{{x - 1}} = \frac{{x - 1 + 1}}{{x - 1}} = \frac{{x - 1}}{{x - 1}} + \frac{1}{{x - 1}} = 1 + \frac{1}{{x - 1}}[/tex]
 
ahh ok... THANKYOU so much, i think it works... subing into the original equation... like 3+1.5 and 3*1.5 both = wooohopo thanks
 
  • #10
meee said:
ahh ok... THANKYOU so much, i think it works... subing into the original equation... like 3+1.5 and 3*1.5 both = wooohopo thanks
You're welcome :smile:
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K