Help finding the answer to DE using method of undetermined coefficients

  • Thread starter lilmul123
  • Start date
  • #1
40
0

Homework Statement



y'' - 5y' = 2x^3 - 4x^2 -x + 6




The Attempt at a Solution



I first found the m's on the left hand side. They are 0 and 5. I then found the m's on the right hand side. They are 0, 0, 0, and 0. I then wrote my interim equation:

y = C1 + C2e^5x + Ax^4 + Bx^3 + Cx^2 + Dx. Because there already is a 0 on the left hand size for m, then there are x's for each part of the equation on the right side.

This is where I'm confused. I have tried to find the coefficients by finding the first and second derivatives of Yp, but I get very odd numbers when I solve for the variables(B = 14/75 and C = 5.324 for example). Am I on the right track or did I screw up somewhere? We have never been presented with irrational coefficients before (as is the case with C), so I'm thinking I did something wrong somewhere...
 

Answers and Replies

  • #2
vela
Staff Emeritus
Science Advisor
Homework Helper
Education Advisor
15,136
1,732
It sounds like you're on the right track. I think you're just making algebraic errors when solving for A, B, C, and D, so double-check your work for mistakes. If you post your actual work in solving for them, others and I can see if we spot any mistakes as well.
 
  • #3
40
0
D'oh. You were right. Thank you!
 
  • #4
35,237
7,056
I don't see anything wrong, but don't use approximations, since that will foul things up. Instead of 5.324, use the exact value.
 
  • #5
40
0
There were no approximations, my algebra was just poor.
 

Related Threads on Help finding the answer to DE using method of undetermined coefficients

Replies
2
Views
2K
Replies
3
Views
476
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
469
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
855
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
3K
Top