If the method of undetermined coefficients is used to find a particular solution
yp (t) to the differential equation y'''-y'=te^(-t)+2cos(t) should
have the form: ?
The Attempt at a Solution
roots= 0, 1
correct answer given however is
t(At + B)e^(-t) + C cos(t) + D sin(t)
I don't know how that t in front got there.. It would make sense if my LHS gave e^-t. but i don't think it does.