(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An air-track glider attached to a spring oscillates with a period of 1.50 s. At t=0s, the glider is 5.60 cm left of the equilibrium position and moving to the right at 40.6 cm/s.

What is the phase constant?

2. Relevant solutions

3. The attempt at a solution

[tex]T=1.50s[/tex]

[tex]\omega=2\pi/T=4.189[/tex]

[tex]1: A cos \phi =-0.056m[/tex]

[tex]2: -\omega A sin \phi =0.406m/s[/tex]

[tex]-A sin \phi=0.406/4.189=0.097[/tex]

Divide equation 2 by equation 1:

[tex] - tan \phi=0.097/-0.056[/tex]

[tex]\phi=1.05 rad[/tex]

However, the correct answer is exactly twice my answer, and also negative of what I got. Can anyone explain what dumb mistake I'm making here? Thanks!

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# Homework Help: Help! I get exactly 1/2 of the correct answer for phase constant calculation

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