Help in deducing a equation for Neutral red

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demander
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Hi to all, hope you can help me with a problem that took me almost all the week

Homework Statement


To find The Pka of Neutral Red, i had to use this expression [tex]\frac{A-A_{HNR}}{A_{NR}-A}[/tex]
So Now I Have to show that [tex]\frac{[NR]}{[HNR^{+}]}=\frac{A-A_{HNR}}{A_{NR}-A}[/tex]
i tried backwards and i did it, but starting from the concnetrations is far more dificult

Homework Equations


i Have to prove that equallity using only this equations
[tex]C_{HNR^{+}} + C_{NR}=C_{Total}[/tex](1)

[tex]A_{HNR^{+}}=\epsilon_{HNR^{+}}.b.C_{total}[/tex](2)

[tex]A_{NR}=\epsilon_{NR}.b.C_{total}[/tex](3)

[tex]A=\epsilon_{HNR^{+}}.b.C_{HNR^{+}} + \epsilon_{NR}.b.C_{NR}[/tex] (4)

The Attempt at a Solution



I tried to solve 4 in order to [tex]C_{HNR^{+}}[/tex] first and then in order to [tex]C_{NR}[/tex].
I arrive to
[tex]C_{HNR^{+}}=\frac{A-\epsilon_{NR}.b.C_{NR}}{\epsilon_{HNR^{+}}.b}[/tex]
[tex]C_{NR}=\frac{A-\epsilon_{HNR^{+}}.b.C_{HNR^{+}}}{\epsilon_{NR}.b}[/tex]

then i did the following, added and subtracted the same value in the fraction numerator, like this:
[tex]C_{NR}=\frac{A+\epsilon_{HNR^{+}}.b.C_{NR}-\epsilon_{HNR^{+}}.b.C_{HNR^{+}}-\epsilon_{HNR^{+}}.b.C_{NR}}{\epsilon_{NR}.b}[/tex]

so i could do:
[tex]C_{NR}=\frac{A+\epsilon_{HNR^{+}}.b.C_{NR}-\epsilon_{HNR^{+}}.b.(C_{HNR^{+}}+C_{NR}}{\epsilon_{NR}.b}[/tex]
and using equation 1 it came
[tex]C_{NR}=\frac{A+\epsilon_{HNR^{+}}.b.C_{NR}-\epsilon_{HNR^{+}}.b.(C_{t})}{\epsilon_{NR}.b}[/tex]
then using equation 2:
[tex]C_{NR}=\frac{A+\epsilon_{HNR^{+}}.b.C_{NR}-A_{HNR^{+}}}{\epsilon_{NR}.b}[/tex]

doing the same thing to HNR it came:
[tex]C_{HNR}=\frac{A+\epsilon_{NR}.b.C_{HNR}-A_{NR}}{\epsilon_{HNR^{+}}.b}[/tex]

So doing the reason
[tex]\frac{[NR]}{[HNR^{+}]}[/tex]=[tex]\frac{\frac{A+\epsilon_{HNR^{+}}.b.C_{NR}-A_{HNR^{+}}}{\epsilon_{NR}.b}}{\frac{A+\epsilon_{NR}.b.C_{HNR}-A_{NR}}{\epsilon_{HNR^{+}}.b}}[/tex]
and it's here where i can't see how can i arrive to the final equation
am i going for the worst way? i thought about this all week and can't find a way to prove what i should :cry:


hope someone can help me, it's kind of urgent
 
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The backwards trying was easy... but if i try to do the reverse... the multiplying term is not to clear how it showed off from the equations i give cause backwards the final term is:
[tex]\frac{C_{NR}(\epsilon_{NR}-\epsilon_{HNR})}{C_{HNR^{+}}(\epsilon_{NR}-\epsilon_{HNR})}}[/tex]
so the thing i don't understand is that term:
[tex](\epsilon_{NR}-\epsilon_{HNR})[/tex] where can it come from from the equation i have?
 
demander said:
[tex]A_{HNR^{+}}=\epsilon_{HNR^{+}}.b.C_{total}[/tex](2)
[tex]A_{NR}=\epsilon_{NR}.b.C_{total}[/tex](3)

Are you sure these are correct? Shouldn't it be:

[tex]A_{HNR^{+}}=\epsilon_{HNR^{+}}.b.C_{HNR^+}[/tex]
[tex]A_{NR}=\epsilon_{NR}.b.C_{NR}[/tex]
 
well i really had a doubt about that... cause i think In the two case, the absorvance is given in function of total conectration... these equations are giving in a protocol of the journal of chemistry, but they simnply say... we used this 4 equations and arrive to this :S
I couldn't seem to find that relation even trying very hard this week
 
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http://jchemed.chem.wisc.edu/Journal/Issues/2001/Mar/PlusSub/JCESupp/JCE2001p0349W.pdf
that's the link to the article... i put the pages needed in the attchments if you can't acess the journal
 

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