Help Intermediate Value Theorem problem

  • Thread starter Thread starter c299792458
  • Start date Start date
  • Tags Tags
    Theorem Value
Click For Summary

Homework Help Overview

The discussion revolves around the Intermediate Value Theorem (IVT) in the context of a function f(x) that is continuous on the interval [0,1] with the condition that f(0) = f(1). The original poster seeks to demonstrate the existence of a point a(n) in the interval [0, 1-(1/n)] such that f(a+(1/n)) = f(a).

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to define a new function g(x) = f(a+(1/n)) - f(a) and considers using the IVT to show that there exists a point where g(x) = 0. Some participants question the necessity of differentiability, noting that the problem may rely solely on continuity.

Discussion Status

The discussion includes attempts to apply the IVT and considerations regarding the differentiability of the function. While one participant suggests that differentiability could simplify the problem using Rolle's theorem, the original poster maintains that continuity is the key aspect. The original poster later indicates that the problem is resolved.

c299792458
Messages
67
Reaction score
0

Homework Statement


I have posted this problem earlier but there was a typo such that the problem didn't make sense... I am still stuck and would appreciate a nudge in the right direction.

I am given that f(x) is continuous on [0,1] and f(0)=f(1)
and I have to show that for any n there exists a point a(n) in [0, 1-(1/n)] s.t. f(a+(1/n))=f(a)


2. Homework Equations
see above


3. The Attempt at a Solution
I have defined a new function, say g(x)= f(a+(1/n))-f(a) and am thinking of using the IVT to prove that there exists a point where g(x)=0 but am not quite sure how.

Thanks!
 
Physics news on Phys.org
If f(x) is differentiable as well then we could appeal to Rolle's theorem and we would be done as you know what the curve looks like.
 
Thanks, hunt_mat. But unfortunately f is not necessarily differentiable. I am quite sure that the question is appealing to just continuity.
 
Hi, the problem is solved. Thanks anyway!
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
3K