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HELP! Mass per unit length equation

  1. Apr 12, 2012 #1
    1. The problem statement, all variables and given/known data

    Ok so using the standard equation v = Sqrt(T/Mu)

    I want to find Mu as a gradient for the first fundamental.

    I've made it into F x lambda = sqrt(T/Mu)

    Then f x 2l = sqrt(T/Mu)

    Then f= sqrt(T/4l^2 Mu)

    As I'm having the tension held by a mass suspended over a pulley.

    f= sqrt(mg/4l^2 Mu)

    Note: Mu is used to represent mass per unit length.

    T is TENSION


    MY QUESTION IS:

    How do I convert f^2= mg / (4l^2 Mu) into a form where I can get Mu as the gradient?

    Thanks.
     
  2. jcsd
  3. Apr 12, 2012 #2
    Any help would be appreciated.
     
  4. Apr 12, 2012 #3
    Does it usually take this long to get a reply? I thought this forum was active.
    If someone can PLEASE help it would really be appreciated.
    Thanks.
     
  5. Apr 15, 2012 #4
    I have concluded that this forum is dead.
     
  6. Apr 15, 2012 #5

    Doc Al

    User Avatar

    Staff: Mentor

    If you had an equation A = B/(Cx), could you solve for x? Same thing.

    (μ is the mass/length. Not sure what you mean when you say you want it 'as the gradient'.)
     
  7. Apr 16, 2012 #6
    I want to make a graph with mass per unit length as a gradient, how do I manipulate that equation to do so?
     
  8. Apr 16, 2012 #7
    First of all there are several approaches to do this.
    I would start by arranging the expression to have no square root.
    If you start with v^2 =T/m (m = mass per unit length) can you arrange this to be
    f^2 = T/(m4L^2)
    There are only 2 experimental variables in your case I think....f and L
    Do you knopw what to plot here that would have m as a part of the gradient? It can be tricky depending on your experience with graph plotting and equations of lines !!!
     
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