(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A thin tube of uniform cross-sectionis sealed at both ends . when it lies horizontally,the middle 5cm length contains mercury and the 2 equal ends contain air at the same pressure P. When the tube is held at an angle 60[tex]\circ[/tex] , then the lengths of the air columns above and below the mercury column are 46 cm and 44.5 cm respectively Calculate the pressure in cm of mercury. The temperature is kep at 30[tex]\circ[/tex]C .

2. Relevant equations

ok i think it can be done with PV= constant eq.

3. The attempt at a solution

well i assumed the area of cross-section to be " a " .i got the initial lengths of the air column as 45.25cm .

but thats it . i think the summation of the pressures should be constant . but the presence of 60[tex]\circ[/tex] has confused me . and therefore im not getting the answer .

i desperately need some hep as this is supposed to be 1 of the easiest ques.

thanx in advance!!!

btw HappY New Year!

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# Homework Help: Help Needed in Pressure and Kinetic theory of GAses!

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