Pressures of a gas in cm of mercury

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SUMMARY

The discussion focuses on calculating the pressure of a gas trapped by a column of 5 cm of mercury using the equation Pressure = h * g * rho. The user correctly deduces that for a gas pressure calculation in cm of mercury, the first case results in 81 cm (76 + 5 cm), the second case results in 71 cm (76 - 5 cm), and the last case remains unchanged at 76 cm. This confirms the application of hydrostatic pressure principles in gas calculations.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with the equation Pressure = h * g * rho
  • Knowledge of the relationship between mercury column height and pressure measurement
  • Basic grasp of units of pressure, specifically cm of mercury
NEXT STEPS
  • Study the derivation and applications of the hydrostatic pressure equation
  • Learn about the conversion between different pressure units, including atm and mmHg
  • Explore the impact of temperature on gas pressure using the Ideal Gas Law
  • Investigate real-world applications of pressure measurement in meteorology and engineering
USEFUL FOR

Students in physics or chemistry courses, educators teaching fluid mechanics, and professionals in fields requiring pressure calculations, such as meteorology and engineering.

Richie Smash
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Homework Statement


Hello, I will post a picture here of a question.
It states, a column of air is trapped by 5cm of mercury as shown.
What is the pressure in cm of mercury in the gas in each case?

Homework Equations


Pressure= h*g*rho

The Attempt at a Solution


I would use that equation but usually density is given in these exams.
They state for the answer to be in cm of mercury,
So my guess is for the first one it’s 76+5cm
For the second it’s 76-5cm
And for them last one it’s 76 cm no change.

How do I figure this out?
 

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Your guess is correct.
 
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