Specific heat capacity of gases

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Homework Help Overview

The problem involves two rigid vessels containing an ideal gas and examines the effects of heat transfer on the pressure and resulting mercury column height in a manometer. The subject area pertains to thermodynamics and the specific heat capacity of gases.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of heat transfer on gas pressure and the movement of mercury in the manometer. There is confusion regarding the assumption that the volume for gas expansion and contraction is negligible, leading to questions about the accuracy of the problem setup.

Discussion Status

Some participants have provided clarifications regarding the assumptions made in the problem, particularly about the volume available for gas expansion. There is an acknowledgment of the need for clearer representation in the problem statement, but no consensus has been reached on the implications of these assumptions.

Contextual Notes

There is a noted discrepancy between the problem's assumptions and the visual representation of the manometer, which may lead to confusion about the behavior of the gases in the vessels.

lavankohsa
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Homework Statement



Figure shows two rigid vessels A and B, each of volume 200 cm3 containing an ideal gas (Cv = 12.5 J/mol-K). The vessels are connected to a manometer tube
containing mercury. The pressure in both the vessels is 75 cm of mercury and the temperature is 300 . (b) 5.0 J
of heat is supplied to the gas in the vessel A and 10 J to the gas in the vessel B. Assuming no appreciable transfer of heat from A to B calculate the difference in the heights of mercury in the two sides of the manometer

10dxlog.png

2. Homework Equations


ΔQ=ΔW+ΔU

3. The Attempt at a Solution


I know that when we give heat to both vessel, the pressure will increase. So the mercury column will also move and there will be a difference in the height in two arms . But my book says when we give heat to vessl there of gas in both vessel will be same. So according to my book ΔW=0 for both vessel. But since mercury will move, one gas should expand and other should compress. Please help me .
 
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They are assuming that the volume available for expansion and contraction of the gases within the manometer tube is negligible.

Chet
 
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OK thanks . But they should mention it .
 
lavankohsa said:
OK thanks . But they should mention it .
Yes, they should, since the figure seems to suggest that there is volume available for gas expansion and contraction in the manometer tube. But it obviously is not drawn to scale.

Chet
 

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