A gun shoots a bullet with a velocity of magnitude 490 m/s. The goal is to hit the target 980 meters away. How high above the target must you aim to correct for gravity? (assume gun and target are same height)
I worked the problem by first getting the x- and y- component equations for position and velocity. I got the x-position equation at final time T, 980 meters=490cos(theta)*T, solved for T, plugged it into the y-position equation at T, 0=-1/2(9.8)T^2 + 490sin(theta)T.
The Attempt at a Solution
Solving for theta, I got about .115 degrees as the answer. The Book says the answer is 1.15 degrees. What did I do wrong? Thank you!