- #1
JoshP-hillips
- 5
- 0
Q1.
x2dy/dx + xy = x2sinx
I believe it is a separable equation (first order linear)
First step is to rewrite into standard form;
dy/dx + (xy)/x2 = (x2sin(x))/x2
Then to calculate the integrating factor I(x);
I(x) = e|(xy)/x2dx = eylnx = elnxy = xy
Then i need to multiply both sides of the d.e. by I(x)
x2dy/dx + xy = x2sinx
I believe it is a separable equation (first order linear)
First step is to rewrite into standard form;
dy/dx + (xy)/x2 = (x2sin(x))/x2
Then to calculate the integrating factor I(x);
I(x) = e|(xy)/x2dx = eylnx = elnxy = xy
Then i need to multiply both sides of the d.e. by I(x)