Help solving/proofing an Integral Equation

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SUMMARY

This discussion focuses on proving the equality of both sides of the integral equation given by the expression $\displaystyle d(X_t^4 - 6tX_t^2 + 3t^2) = (4X_t^3 - 12tX_t)\, dX_t$. The proof utilizes Ito's lemma, where the function $f(t, x) = x^4 - 6tx^2 + 3t^2$ is differentiated to show that the differential form simplifies to the required equality. The key steps involve calculating the partial derivatives and applying the lemma correctly, confirming the equality holds under the assumption that $X_0 = 0$.

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cdbsmith
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Need help showing that both sides of the following integral are equal. Any help would be greatly appreciated.
 

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cdbsmith said:
Need help showing that both sides of the following integral are equal. Any help would be greatly appreciated.

Since the integral equation is given (and assuming $X_0 = 0$), it suffices to show

$\displaystyle d(X_t^4 - 6tX_t^2 + 3t^2) = (4X_t^3 - 12tX_t)\, dX_t$.

To do this, set $f(t, x) = x^4 - 6tx^2 + 3t^2$ and apply Ito's lemma to get

$\displaystyle df(t, X_t) = \left(f_t + \frac{f_{xx}}{2}\right) dt + f_x \, dX_t$,

$\displaystyle df(t, X_t) = \left(-6X_t^2 + 6t + \frac{12X_t^2 - 12t}{2}\right) dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle df(t, X_t) = (-6X_t^2 + 6t + 6X_t^2 - 6t)\, dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle df(t, X_t) = 0\, dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle d(X_t^4 - 6tX_t^2 + 3t^2) = (4X_t^3 - 12tX_t)\, dX_t$.
 
Euge said:
Since the integral equation is given (and assuming $X_0 = 0$), it suffices to show

$\displaystyle d(X_t^4 - 6tX_t^2 + 3t^2) = (4X_t^3 - 12tX_t)\, dX_t$.

To do this, set $f(t, x) = x^4 - 6tx^2 + 3t^2$ and apply Ito's lemma to get

$\displaystyle df(t, X_t) = \left(f_t + \frac{f_{xx}}{2}\right) dt + f_x \, dX_t$,

$\displaystyle df(t, X_t) = \left(-6X_t^2 + 6t + \frac{12X_t^2 - 12t}{2}\right) dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle df(t, X_t) = (-6X_t^2 + 6t + 6X_t^2 - 6t)\, dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle df(t, X_t) = 0\, dt + (4X_t^3 - 12tX_t)\, dX_t$,

$\displaystyle d(X_t^4 - 6tX_t^2 + 3t^2) = (4X_t^3 - 12tX_t)\, dX_t$.

Thanks, Euge!

I'm going to study your solution and try to understand it. I will let you know if I get stuck on something.

Thanks again!
 

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