Help to convert units of a simple formula

[Safinaz]

Homework Statement

Consider the following formula

Relevant Equations

$p = k^2/ H^2$, where k is a variable of units Hz and H is a constant $H= 10^{14}$ GeV

The value of H equals $10^{3}$ in natural units,

According to : https://en.wikipedia.org/wiki/Natural_units, $t \sim 10^{-21} sec = 10^{21} Hz$, and since $\text{GeV} \sim 10^{24} \text{Hz }$,
$GeV \sim 10^{24} \times 10^{-21} = 10^3$ in natural units.

So is this conversion correct?

Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?

 

[haruspex]

Homework Statement: Consider the following formula
Relevant Equations: $p = k^2/ H^2$, where k is a variable of units Hz and H is a constant

I do not see what those have to do with the rest of your question.

$H= 10^{14}$ GeV

The value of H equals $10^{3}$ in natural units,

Don’t those imply GeV=$10^{-11}$ in natural units?

According to : https://en.wikipedia.org/wiki/Natural_units,

That link lists six different systems. Which one are you using?

$t \sim 10^{-21} sec = 10^{21} Hz$,

So it’s particle and atomic physics, right?

and since $\text{GeV} \sim 10^{24} \text{Hz }$,

So not $10^{-11}$?