Wiki's entry on the "electron volt" lists all the conversion factors except for the density.June_cosmo said:Homework Statement
Convert 1 ##Gev## to Kelvin, and convert ##GeV^{-1}## to meters, seconds, and convert ##GeV^4## to density ##(kg/ m^3).##
Homework Equations
natural units ##c=h=k_B=1##
The Attempt at a Solution
I know to convert energy to meters, I can use
##\lambda =hc/E##, I get the result ##GeV^{-1}=8.05*10^{14}m##
But I don't know what other formulas I should use in order to complete the other conversions. Thanks for any hint!
The energy unit is a measurement of the amount of energy in a system. It is typically measured in joules (J) or calories (cal).
To convert energy units to kelvin, you can use the formula E = kT, where E is energy, k is the Boltzmann constant (1.38 x 10^-23 J/K), and T is temperature in kelvin. Simply rearrange the formula to solve for T.
Energy and time are both fundamental units in physics. The relationship between them is defined by the equation E = Pt, where E is energy, P is power (measured in watts), and t is time in seconds. This equation shows how energy is the product of power and time.
Density is a measure of how much mass is contained in a given volume. It is typically measured in kilograms per cubic meter (kg/m^3). To find the density of an object, you divide its mass by its volume.
Length and energy units are two different types of measurements. Length is a measure of distance, while energy is a measure of the ability to do work. They are related in some equations, such as the equation for potential energy (PE=mgh), where length (h) is a factor in determining energy. However, they cannot be directly converted between each other.