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Could someone please help me simplify the equation:

[itex]\frac{-1}{(c1+c2)}[/itex][itex] [/itex] [itex]\cdot[/itex] ln [(m1-m2)g-(c1+c2)v] = [itex]\frac{t}{(m1+m2)}[/itex] - [itex]\frac{1}{(c1+c2)}[/itex] [itex]\cdot[/itex] ln[(m1-m2)g]

(where c1, c2, m1, m2, g, are constants)

so as to get: v = [itex]\frac{(m1-m2)g}{(c1+c2)}[/itex] [itex]\cdot[/itex] [ 1 - exp[[itex]\frac{-(c1+c2)t }{(m1+m2)}[/itex]]] (teacher's solution)?

I tried several ways to solve the equation for v (applying e^ to it), but all i can seem to get is:

v = [exp[itex]\frac{t}{(m1+m2)}[/itex]] / [(c1+c2) * exp[itex]\frac{1}{(c1+c2)}[/itex]]

Thanks.

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# Homework Help: Help to simplify a difficult equation

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