I did this problem, yet I found out that its wrong because I didn't plug the correct force in. I have no idea what to do now though. If someone can show me what I did wrong and explain it, I would greatly appreciate that. Thank you! Two coins with identical charges are placed on a lab table 1.35 m apart. A.If each coin experiences a force of 2.0 N because of the presence of the other coin, calculate the charge on each coin. FE=KE (q1q2/r^2) R^2 = 1.35m q1q2 = 2.0N FE=KE (2.0N*2.0N)/(1.35^2m) FE=2.194 or 2.195 A B.Would the force be classified as a force of attraction or repulsion? Explain your answer. Force of attraction because it represents a weight.