Undergrad Help with a 3D Line Integral Problem (segmented line)

Click For Summary
The discussion focuses on solving a 3D line integral problem involving three segments: C1, C2, and C3. The user is seeking guidance on how to set up and evaluate the integrals, initially expressing confusion about the contributions of dz and dy. Clarifications are provided on how to parametrize each segment and the correct integrand for C1, which leads to a realization that the integral evaluates to zero due to z being constant. Ultimately, after calculating the integrals for all segments and summing them, the user arrives at a final answer of 7/2, confirming the approach of separating the integrals and adding them together.
SK97
Messages
32
Reaction score
0
TL;DR
Line integral problem involving 3 segmented lines along the xyz plane.
Need some help on how to begin to tackle the problem.
Hi all,

I'm finding it difficult to start this line integral problem.

I have watched a lot of videos regarding line integrals but none have 3 line segments in 3D.

If someone can please point me in the right direction, it would help a lot.

I've put down the following in my workings:

C1: (0,0,0) - (1,0,0)

C2: (1,0,0) - (1,1,0)

C3: (1,1,0) - (1,1,1,1)

How do I proceed from here?

Thank you in advance!
 

Attachments

  • Screen Shot 2020-05-05 at 05.59.53.png
    Screen Shot 2020-05-05 at 05.59.53.png
    15.8 KB · Views: 332
Physics news on Phys.org
On ##C_1## dz=dy=0, so only ##\int dz## survives.
On ##C_2## and ##C_3##, similarly you should make one integral out of the three.
 
  • Like
Likes SK97
anuttarasammyak said:
On ##C_1## dz=dy=0, so only ##\int dz## survives.
On ##C_2## and ##C_3##, similarly you should make one integral out of the three.

Okay, so i form three integrals and combine them?

Also that's where i am confused, when i am doing C1 shouldn't the 3dz go away too as its treated as a constant?
 
(correction) only ##\int dx## survives.
So for ##C_1## the integral is ##\int_{C_1} x^2z \ dx## where z is ...
 
  • Like
Likes SK97
anuttarasammyak said:
(correction) only ##\int dx## survives.
So for ##C_1## the integral is ##\int_{C_1} x^2z \ dx## where z is ...

So for C1 i have the parametrisation as r(t) = <t,0,0>

I got this by doing:
x= t(1) + (1-t)(0) = t

and zeros for the others.

Is this the correct way to evaluate it?
 
SK97 said:
I got this by doing:
x= t(1) + (1-t)(0) = t

and zeros for the others.
So the integrand ##x^2z## on ##C_1## is ...
 
anuttarasammyak said:
So the integrand ##x^2z## on ##C_1## is ...
just t^2 dx right?
 
\int x^2z \ dx = z\int x^2 dx =..
 
anuttarasammyak said:
\int x^2z \ dx = z\int x^2 dx =..
so replacing x with t we get t^2 in the integral but since z= 0 do we get 0 for c1?

sorry if I'm understanding incorrectly
 
  • #10
:thumbup:
 
  • #11
anuttarasammyak said:
:thumbup:
oh thank you so much, so similar set up then for the other integrals and then at the end its just addition of them all, correct?
 
  • #12
:smile:
 
  • Like
Likes SK97
  • #13
anuttarasammyak said:
:smile:
Thanks a lot! hopefully i don't run into other issues but please be around to help out!

will greatly appreciate it :)
 
  • #14
SK97 said:
Thanks a lot! hopefully i don't run into other issues but please be around to help out!

will greatly appreciate it :)
so i finished calculating for all C values and after the addition got to 7/2 as the answer.

does that seem right to you?
 
  • #15
Seperate it into the sum of 3 intgrals over c1 c2 and c3. Then parametrize each path. Plug everything in, calculate dx dy and dz in Terms of dt, calculate the 3 integrals then. Add them, and you are done.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
4K