Help with a relativity question

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The discussion revolves around solving a problem related to travel time on a moving sidewalk at an airport. Participants are trying to determine the time it takes to walk from the gate to baggage claim when the moving sidewalk is operational. They mention using ratios and derivatives to approach the problem, with one user providing a formula for calculating time based on distance and speeds. The conversation clarifies the scenarios of walking versus standing on the moving sidewalk and the need to consider both sections of the airport. Ultimately, the goal is to find the travel time when both walking and the moving sidewalk are in use.
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1. ok, my dad and I are trying to solve this problem, but we're both having difficulty:
"When the moving sidewalk at the airport is broken, as it often seems to be, it takes you 50 s to walk from your gate to baggage claim. When it is working and you stand on the moving sidewalk the entire way, it takes 75 s to travel the same distance. How long will it take you to travel from the gate to baggage claim?





3. I think it has something to do with ratios, but he said something about derivatives. Please help!
 
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t=d/(v1+v2)=d/(d/t1 +d/t2)=t1*t2/(t1+t2)

Should help?
 
How long will it take you to travel from the gate to baggage claim?

Still trying to find out what you are asking:

4 scenarios:
Broken -- standing = ∞ s
Broken -- walking = 50 s
Working --standing = 75 s
Working --walking = ? is this what you are trying to find out?
 
i believe so. the question is asking how long will it take to get to baggage claim if the machine is working and you are walking on in.
 
Are we thinking (like in regular airports) there is a section, d1, of a non-moving floor and a section, d2, of a moving sidewalk?
 
yes i think so. i copied the question exactly.
iRaid- how did you get from d/(d/t1+d/t2)=t1*t2/t1+t2?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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